b^2-b-108=0

Solution for b^2-b-108=0 equation:

b^2-b-108=0

We add all the numbers together, and all the variables

b^2-1b-108=0

a = 1; b = -1; c = -108;
Δ = b2-4ac
Δ = -12-4·1·(-108)
Δ = 433
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{433}}{2*1}=\frac{1-\sqrt{433}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{433}}{2*1}=\frac{1+\sqrt{433}}{2}
$